Answer:
The 20th term is;
[tex]a_{20}=-131[/tex]Explanation:
Given the arithemetic sequence;
[tex]2,-5,-12,-19,\ldots[/tex]The first term is 2;
[tex]a=2[/tex]The common difference d is;
[tex]\begin{gathered} d=-5-2 \\ d=-7 \end{gathered}[/tex]The nth term of an arithemetic sequence can be calculated using the formula;
[tex]a_n=a+(n-1)d[/tex]substituting for the 20th term, n=20;
[tex]\begin{gathered} a_{20}=2+(20-1)(-7) \\ a_{20}=2+(19)(-7) \\ a_{20}=2-133 \\ a_{20}=-131 \end{gathered}[/tex]Therefore, the 20th term is;
[tex]a_{20}=-131[/tex]