Algebra 2 real world compositions.A rock is dropped into a pond. What is the spread of the circular ripple after 25 seconds if the ripple travels outward at a speed of 20 cm/sec? Solve using composite functions

Respuesta :

According to the statement of the problem:

• we know that the ripple travels outward at a speed ,v = 20 cm/s,,

,

• we must compute the spread of the circular ripple after a time ,t = 25 s,, i.e. we must compute the distance travelled by the ripple after that time.

Because the ripple travels at a constant velocity, the distance travelled after the time t, is given by:

[tex]r(t)=v\cdot t=20\frac{\operatorname{cm}}{s}\cdot25s=20\cdot25\operatorname{cm}=500\operatorname{cm}\text{.}[/tex]

The area of the circular ripple in terms of its radius is given by the following formula:

[tex]A=\pi\cdot r^2.[/tex]

Because the radius is a function of the time, we have that the area is also a function of time:

[tex]A(t)=\pi\cdot(r(t))^2=\pi\cdot(v\cdot t)^2=\pi\cdot v^2\cdot t^2.[/tex]

Replacing the values v = 20 cm/s and t = 25 s, we have that:

[tex]A(t)=\pi\cdot(20\frac{cm}{s}\cdot25s)^2=\pi\cdot(500\operatorname{cm})^2=25000\pi\cdot cm^2\cong785398.16cm^2.[/tex]

Answer

The circular ripple has a radius of 500 cm and its area is 25000π cm² ≅ 785398.16 cm².