In 2.0 s, a particle moving with constant acceleration along the x axis goes from x = 10 m to x = 50 m. The velocity at the end of this time interval is 10 m/s. What is the acceleration of the particle?

Respuesta :

ANSWER

-10 m/s²

EXPLANATION

The displacement of the particle is,

[tex]\Delta x=50m-10m=40m[/tex]

We know that the final velocity is 10m/s, after 2 seconds. To find the acceleration, we have to find the initial velocity too.

We know that the displacement is,

[tex]\Delta x=\frac{v_i+v_f}{2}\cdot t[/tex]

Solving for the initial velocity vi,

[tex]v_i=\frac{2\Delta x}{t}-v_f[/tex]

Replace with the values,

[tex]v_i=\frac{2\cdot40m}{2s}-10m/s=40m/s-10m/s=30m/s[/tex]

The final velocity is also a function of the acceleration,

[tex]v_f=v_i+a\cdot t[/tex]

Solving for a,

[tex]a=\frac{v_f-v_i}{t}[/tex]

Replace with the values,

[tex]a=\frac{10m/s-30m/s}{2s}=\frac{-20m/s}{2s}=-10m/s^2[/tex]

Hence, the acceleration of the particle is -10m/s².