ANSWER
-10 m/s²
EXPLANATION
The displacement of the particle is,
[tex]\Delta x=50m-10m=40m[/tex]We know that the final velocity is 10m/s, after 2 seconds. To find the acceleration, we have to find the initial velocity too.
We know that the displacement is,
[tex]\Delta x=\frac{v_i+v_f}{2}\cdot t[/tex]Solving for the initial velocity vi,
[tex]v_i=\frac{2\Delta x}{t}-v_f[/tex]Replace with the values,
[tex]v_i=\frac{2\cdot40m}{2s}-10m/s=40m/s-10m/s=30m/s[/tex]The final velocity is also a function of the acceleration,
[tex]v_f=v_i+a\cdot t[/tex]Solving for a,
[tex]a=\frac{v_f-v_i}{t}[/tex]Replace with the values,
[tex]a=\frac{10m/s-30m/s}{2s}=\frac{-20m/s}{2s}=-10m/s^2[/tex]Hence, the acceleration of the particle is -10m/s².