Explanation
Step 1
if you have two points P1 and P2 of a line, the slope is given by:
[tex]\text{slope}=\frac{y_2-y_1}{x_2-x_1}[/tex]where
[tex]\begin{gathered} P1(x_1,y_1)_{}_{} \\ P2(x_2,y_2)_{} \end{gathered}[/tex]a)Let
P1(4,0) P2(9,7)
b) replace
[tex]\begin{gathered} \text{slope}=\frac{y_2-y_1}{x_2-x_1} \\ \text{slope}=\frac{7-0}{9-4} \\ \text{slope}=\frac{7}{5} \end{gathered}[/tex]Step 2
usin P1 (4,0) and the slope find the point-slope form equaton
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ y-0=\frac{7}{5}(x-4) \\ y=\frac{7}{5}x-4 \end{gathered}[/tex]