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Define a variable, set up an inequality, and solve. Only algebraic solutions are accepted. “Chris is on vacation at a lake house for the weekend and decided to rent a canoe for the day. If they charge a $10 service fee plus $38 per hour, and he can spend at most $200, how many hours can he rent the canoe?”

Respuesta :

if x=hours, the amount of money he needs is 10 +38*x

he can spend at most 200, so:

[tex]\begin{gathered} 10+38x\leq200 \\ \end{gathered}[/tex]

and now we can solve:

[tex]\begin{gathered} 38x\leq200-10 \\ 38x\leq190 \\ x\leq\frac{190}{38} \\ x\leq5 \end{gathered}[/tex]

so the answer is: he can rent the canoe at most 5 hours

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