Jacob invests $8,788 in a savings account with a fixed annual interest rate compounded 6 times per year. After 4 years, the balance reaches $11,490.08. What is the interest rate of the account?

Respuesta :

Given that the principal (P) is $8,788, time (T) is 4 years.

Let R be the annual rate of interest.

Given that the compounding is done 6 times a year, then the rate of interest per period and the number of periods is calculated as,

[tex]\begin{gathered} r=\frac{R}{6} \\ n=6\times T=6\times4=24 \end{gathered}[/tex]

Consider the formula for amount (A) as,

[tex]A=P(1+\frac{r}{100})^n[/tex]

Substitute the values and simplify,

[tex]\begin{gathered} 11490.08=8788(1+\frac{R}{600})^{24} \\ (1+\frac{R}{600})^{24}=\frac{11490.08}{8788} \\ 1+\frac{R}{600}=(1.3075)^{\frac{1}{24}} \\ 1+\frac{R}{600}=1.01123 \\ \frac{R}{600}=0.01123 \\ R\approx6.74 \end{gathered}[/tex]

Thus, the annual interest rate of the account is 6.74% approximately.