We have,
Q= ne;
Here,
Q= total charge;
n= number of electrons;
e = charge of one electron;
Using above formula
[tex]\begin{gathered} Q=\text{ ne;} \\ 10.98\text{ }\times10^{-6\text{ }}\text{ = n }\times1.6\times10^{-19}\begin{cases}Q={10.98\times10^{-6}\text{ C}} \\ e={1.6\times10^{-19}C}\end{cases} \\ \therefore n=\text{ }\frac{10.98\times10^{-6}}{1.6\times10^{-19}}=\text{ 6.8625}\times10^{13} \end{gathered}[/tex]Note:
[tex]1\text{ microC= 10}^{-6}C[/tex][tex]\text{ Answer is }6.8625\times10^{13}\text{ ;}[/tex]