Respuesta :
Answer
1.74 × 10²⁴ molecules are present in 214 g of calcium hydroxide.
Explanation
Step 1: Calculate the moles of calcium hydroxide in 214 g using the mole formula.
The molar mass of calcium hydroxide = 74.093 g/mol
[tex]Mole=\frac{Mass}{Molar\text{ }mass}=\frac{214\text{ }g}{74.093\text{ }g\text{/}mol}=2.888262049\text{ }mol[/tex]Step 2: Convert 2.888262049 moles of calcium hydroxide to molecules using Avogadro's constant.
Conversion factor: 1 mole of any substance = 6.022 × 10²³ molecules.
∴ 2.888262049 moles of calcium hydroxide is equal to
[tex]\frac{2.888262049\text{ }mol}{1\text{ }mol}\times6.022\times10^{23}\text{ }molecules=1.74\times10^{24}\text{ }molecules[/tex]Hence, 1.74 × 10²⁴ molecules are present in 214 g of calcium hydroxide.
