A medical practice group consists of seven doctors, 4 women and 3 men. The women are Drs. Jonswold, Hein, O'Conell, and Lee. The men are Drs. Penner, Paquette, and Marland. Supposenew patients are randomly assigned to one of the doctors in the group.

A medical practice group consists of seven doctors 4 women and 3 men The women are Drs Jonswold Hein OConell and Lee The men are Drs Penner Paquette and Marland class=

Respuesta :

The probability can be converted to percentage by multiplying it with 100. In our case, the probability is 3/7, which is equivalent to 0.428571. Then, by multiplying this number by 100, we get

[tex]0.428571\times100=42.8571\text{ \%}[/tex]

Therefore, by rounding to the nearest tenth, the answer is 42.9 %.