First, let us set x for the missing number.
Then, two-thirds of a number: 2/3 x
exceeds one-half of the number 1/2 by 3
So,
[tex]\frac{2}{3}x-\frac{1}{2}x=3[/tex]Solve for x:
Multiply both sides by 6:
[tex]\begin{gathered} 6(\frac{2}{3}x-\frac{1}{2}x)=6\ast3 \\ \frac{12}{3}x-\frac{6}{2}x=18 \\ 4x-3x=18 \\ x=18 \end{gathered}[/tex]Hence, the number is 18.
