Given the algebraic expression below
[tex]6x(y^2z)[/tex]Given data
[tex]x=\frac{1}{2},y=-1,and\text{ z=2}[/tex]Let us now solve for the value of the algebraic expression by substituting the values of x, y, and z respectively into the expression above.
[tex]6(\frac{1}{2})((-1)^2(2))=3((1)(2))=3(2)=3\times2=6[/tex]Therefore, the value of the algebraic expression is 6.
The correct option is Option D.
