Given:
[tex]\begin{gathered} y=2x-1\text{ } \\ 2x+y=3 \end{gathered}[/tex]Find: solve the given equations by substitution method
Explanation:
[tex]\begin{gathered} y=2x-1.................(1) \\ 2x+y=3.................(2) \end{gathered}[/tex]put the value of y from equation (1) into equation (2) .
[tex]\begin{gathered} 2x+2x-1=3 \\ 4x=4 \\ x=\frac{4}{4}=1 \\ y=2x-1 \\ =2\times1-1 \\ =2-1 \\ =1 \end{gathered}[/tex]Final answer: the required solution is x=1 and y=1.
