Answer
[tex]p(even\text{ }or\text{ }less\text{ }than\text{ }6)=\frac{7}{9}[/tex]Explanation
The result of a pair of six-sided dice rolled and their total is shown below:
The sample size = 36
The even number in the sample size = 18
The number less than 6 in the sample size = 10
Therefore, the probability that the sum of the numbers on your dice is an even number or a number less than 6 = p(even number) + p(number less than 6)
[tex]p(even\text{ }or\text{ }less\text{ }than\text{ }6)=\frac{18}{36}+\frac{10}{36}=\frac{28}{36}=\frac{7}{9}[/tex]
