Respuesta :

D

1) Let's verify both values for x so that we can find it:

[tex]\begin{gathered} 15,22 \\ a)45-15>30 \\ 30>30\text{ FALSE} \\ 45-22>30 \\ 23>30False \\ \\ b)x+8\leq23 \\ 15+8\leq23\text{ \lparen T\rparen}\Rightarrow23\leq23\left(T\right? \\ 22+8\leq23\left(F\right)\Rightarrow30\leq23\text{ \lparen F\rparen} \\ \\ c)17+x>32 \\ 17+15>32 \\ 32>32\left(F\right) \\ 17+22>32 \\ 39>32\left(T\right) \\ \\ d)2x-16\leq29 \\ 2\left(15\right?-16\leq29 \\ 14\leq29\left(T\right) \\ 2\left(22\right)-16\leq29 \\ 44-16\leq29 \\ 28\leq29\left(T\right? \end{gathered}[/tex]

2) As the only inequality which holds true for 15 and 22 is d, then the answer is:

D