Given
The incident angle is
[tex]i=42^o[/tex]The index of refraction is n=1.5
To find
The angle of refraction
Explanation
We know,
[tex]\begin{gathered} n=\frac{sini}{sinr} \\ \Rightarrow1.5=\frac{sin42^0}{sinr} \\ \Rightarrow sinr=\frac{sin42^o}{1.5} \\ \Rightarrow sinr=0.44 \\ \Rightarrow r=26.10^o \end{gathered}[/tex]Conclusion
The angle of refraction is 26.10 deg
