Solution
We have the following solution:
[tex]x^2+4x+19=0[/tex]
And we can use the following equation:
[tex]x=\frac{-\text{b}\pm\sqrt[]{b^2-4ac}}{2a}[/tex]
For this case a=1, b=4, c=19
Replacing we got:
[tex]x=\frac{-4\pm\sqrt[]{(4)^2-4(1)(19)}}{2(1)}=\frac{-4\pm\sqrt[]{-60}}{2}=-2\pm\sqrt[]{15}i[/tex]
Then the answers are:
[tex]x=-2-\sqrt[]{15}i,-2+\sqrt[]{15}i[/tex]
