Given data:
* The mass of the water is 0.65 kg.
* The initial temperature of the water is 20 degree celsius.
* The final temperature of the water is 43 degree celsius.
Solution:
The amount of heat added to the water to increase its temperature is,
[tex]Q=\text{mcdT}[/tex]where m is the mass, c is the specific heat, and dT is the change in the temperature,
Substituting the known values,
[tex]\begin{gathered} Q=0.65\times1\times(43^{\circ}-20^{\circ}) \\ Q=14.95\text{ kcal} \end{gathered}[/tex]Thus, the amount of heat added to the water is 14.95 kcal or approximately 15 kcal.
