Givens.
• The pulling force 185 N.
,• The angle is 25 degrees.
,• The mass is 35 kg.
,• The coefficient of friction is 0.45.
Let's use Newton's Second Law to find an expression.
[tex]\begin{gathered} \Sigma F_x=ma\to F\cdot\cos \theta-\mu mg=ma \\ 185N\cdot\cos 25-0.45\cdot35\operatorname{kg}\cdot9.81\cdot\frac{m}{s^2}=ma \\ 167.67N-154.51N=35\operatorname{kg}\cdot a \\ a=\frac{13.16}{35}\cdot\frac{m}{s^2} \\ a=0.38\cdot\frac{m}{s^2} \end{gathered}[/tex]Therefore, the acceleration of the box is 0.38 m/s^2.
