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Unpolarized light with intensity 436.92 W/m2 passes first through a polarizing filter with its axis vertical, then through a polarizing filter with its axis 21.73o from vertical. What light intensity emerges from the second filter ?

Respuesta :

Given:

Initial intensity, Io = 436.92 W/m²

Angle = 21.73⁰

Let's find the light intensity that emerges from the second filter.

Apply the formula:

[tex]I_2=\frac{1}{2}*I_o*cos^2\theta[/tex]

Where:

I₂ is the light intensity from the second filter.

Thus, we have:https://assets.grammarly.com/emoji/v1/1f454.svg

[tex]\begin{gathered} I_2=\frac{1}{2}*436.92*cos^2(21.73) \\ \\ I_2=218.46*0.8629 \\ \\ I_2=188.52\text{ W/m}^2 \end{gathered}[/tex]

Therefore, the light intensity that emerges from the second filter is 188.52 W/m².

ANSWER:

188.52 W/m²

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