Answer:
15.12 m
Explanation:
The magnitude of a vector (x, y) can be calculated as
[tex]\sqrt{x^2+y^2}[/tex]
So, replacing x by -12 m and y by -9.2 m, we get
[tex]\begin{gathered} \sqrt{(-12)^2+(-9.2)^2} \\ \sqrt{144+84.64} \\ \sqrt{228.64} \\ 15.12\text{ m} \end{gathered}[/tex]
Therefore, the magnitude of the vector is 15.12 m
