[tex]\begin{gathered} \frac{1}{2}x+6y=12\ldots\ldots\text{.(i)} \\ \\ y=x+15\ldots\text{.}\mathrm{}(ii) \\ \text{Let's substitute for y in equation (i)} \\ \\ \frac{1}{2}x+6(x+15)=12 \\ To\text{clear the fraction by multiplying all through by } \\ x+2\times6(x+15)=12\times2 \\ x+12(x+15)=24 \\ \text{open the bracket, by multplying by 12} \\ x+12x+180=24 \\ 13x+180=24 \\ \text{collect the like terms} \\ 13x=24-180 \\ 13x=-156 \\ \text{Divide both sides by 13} \\ \frac{13x}{13}=\frac{-156}{13} \\ x=\text{ -12} \end{gathered}[/tex]
TO FIND Y
Substitute for x in Equation (ii)
y=x+15
y=-12+15
y=3
THE FINAL ANSWER
X=-12 AND Y=3
