Given data:
The first given length is AB =36.
The second given length is BC =58.
The third given length is DE =32.
The expression for AC length is,
[tex]\begin{gathered} AC=2(DE) \\ =2(32) \\ =64 \end{gathered}[/tex]
The expression for DF length is,
[tex]\begin{gathered} DF=\frac{1}{2}BC \\ =\frac{1}{2}(58) \\ =29 \end{gathered}[/tex]
The expression for CF length is,
[tex]\begin{gathered} CF=\frac{1}{2}(AC) \\ =\frac{1}{2}(64) \\ =32 \end{gathered}[/tex]
Thus, AC is 64, DF is 29, and CF is 32.
