Suppose a normal distribution has a mean of 79 and astandard deviation of 7.

The probability can be calculated using the z-score:
[tex]z=\frac{x-\bar{x}}{\sigma}[/tex]From the question, the following parameters are given:
[tex]\begin{gathered} x=72 \\ \bar{x}=79 \\ \sigma=7 \end{gathered}[/tex]The z-score is calculated as follows:
[tex]\begin{gathered} z=\frac{72-79}{7}=-\frac{7}{7} \\ z=-1 \end{gathered}[/tex]The probability is calculated using tables. Therefore:
[tex]P(z\geq-1)=0.8413[/tex]The correct option is OPTION C.