If ángulo TUV is isósceles find the value of x.

1) Given that ΔTUV is isosceles, so at least two angles are congruent to each other, and as it is indicated because of that the measure of two sides are also congruent to each other.
Leg TU ≅ UV
2) Therefore we can write
∠VTU ≅∠ UVT
8x -42º + 43º+43º = 180º
8x -42º +86º =180º
8x +44 = 180 Subtract 44 from both sides
8x =136º Divide both sides by 8
x = 136/8
x=17
3) So the value of x, is 17