A) x =-1/36y²
1) Considering that the Vertex is on the origin (0,0) and the Focus is at (-9, 0)
Then we can write out:
y² =-2px p is the parameter
F= (-p/2, 0) Since the Focus is at (-9,0)
-p/2 = 9
-p = 18
p= -18
[tex]\begin{gathered} y^2=-2.18x \\ y^2=-36x\text{ } \\ or \\ x=-\frac{1}{36}y^2 \\ \end{gathered}[/tex]
2) Hence, the answer is x=-1/36y².
