what is the line of sight distance from the television camera to the base of the stadium?

Given the following information
television camara at 13°
altitude = 400
since the formed angle is a 90° angle then
90-13= 77
The trigonometric function that relates Hyp angle and Adj is Cos
then
[tex]Cos(\theta)=\frac{Adj}{Hyp}[/tex]where
angle = 77
adj=400
Hyp= distance from camara to thestadium =?
then
[tex]Cos(77)=\frac{400}{Hyp}[/tex][tex]Hyp=\frac{400}{Cos(77)}[/tex][tex]Hyp=\frac{400}{Cos(77)}[/tex][tex]Hyp=\frac{400}{0.22495}[/tex][tex]Hyp=1778.1645[/tex]Round to the nearest meter
the line of the sight is approximately
1778 m