Step 1
Given;
[tex]\begin{gathered} Total\text{ number of coins=15} \\ Total\text{ number of gold=8} \\ Total\text{ number of silver=7} \\ \end{gathered}[/tex]
Required; 5 coins are randomly drawn. What is the probability that 2 of the coins drawn are gold and 3 are silver?
Step 2
Where;
[tex]\begin{gathered} P=\frac{8}{15},\text{ x=2} \\ P(2)=\frac{5!}{2!(5-2)!}(\frac{8}{15})^2(1-\frac{8}{15})^{5-2} \\ =0.28907983539095 \\ \approx0.29 \end{gathered}[/tex]
Answer;
[tex]0.29\text{ to 2 decimal places}[/tex]
