We can find the length of the line with end points C and D using the formula for the distance between two points:
[tex]d(C,D)=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]then, in this case we have the following:
[tex]\begin{gathered} C=(0,-2) \\ D=(0,9) \\ \Rightarrow d(C,D)=\sqrt[]{(0-0)^2+(9-(-2))^2} \\ =\sqrt[]{(9+2)^2}=\sqrt[]{11^2}=11 \\ d(C,D)=11 \end{gathered}[/tex]therefore, the length of the line with end points C and D is 11 units.
