The opposites angle of a parallelogram are equal. So,
[tex]\begin{gathered} \angle ABC=\angle CDA \\ \angle ABC=112 \end{gathered}[/tex]
Determine the measure of angle CBE.
[tex]\begin{gathered} \angle CBE+\angle ABC=180 \\ \angle CBE+112=180 \\ \angle CBE=68 \end{gathered}[/tex]
Since CE = BE, so oppostie angle to side BE and CE are equal.
[tex]\begin{gathered} \angle CBE=\angle BCE \\ \angle BCE=68 \end{gathered}[/tex]
Consider the traingle BCE.
The sum of three angles of a triangle is 180. So,
[tex]\begin{gathered} \angle CBE+\angle BCE+\angle CEB=180 \\ 68+68+\angle CEB=180 \\ \angle CEB=180-136 \\ =44 \end{gathered}[/tex]
Thus measure of angle E is 44 degree.
