Step1: write out the given parameters from the question
[tex]\begin{gathered} \text{diameter}=8ft \\ \text{height}=\text{ 12ft} \end{gathered}[/tex]
Step2: write out the formula
[tex]\begin{gathered} \text{volume of cone=}\frac{1}{3}\pi r^2h \\ \text{where r=}\frac{\text{8}}{2}=4,\text{ h=12} \end{gathered}[/tex]
Step3: substitute the values into the formula
[tex]\text{volume of cone=}\frac{1}{3}\times3.14\times4^2\times12[/tex][tex]\begin{gathered} =3.14\times16\times4 \\ =200.96ft^3 \end{gathered}[/tex]
Therefore the volume of the cone is 200.96ft³
