Answer:
-1.22 m/s
Explanation:
To find the initial velocity, we will use the following equation:
[tex]d=\frac{1}{2}(v_i+v_f)t[/tex]Where d is the displacement, t is the time, vi is the initial velocity and vf is the final velocity.
So, replacing vf by 7.8 m/s, t by 5.7s, and d by 18.75 m, we get:
[tex]18.75=\frac{1}{2}(v_i+7.8)(5.7)[/tex]Now, we can solve for vi:
[tex]\begin{gathered} \frac{18.75}{5.7}=\frac{1}{2}(v_i+7.8) \\ 3.29=\frac{1}{2}(v_i+7.8) \\ 3.29\times2=v_i+7.8 \\ 6.58=v_i+7.8 \\ 6.58-7.8=v_i \\ -1.22m/s=v_i \end{gathered}[/tex]Therefore, the initial velocity of the bike was -1.22 m/s
