The slope of the line that passes through the points (x1, y1) and (x2, y2) is computed as follows:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]then, the line that passes through the points (3, 11) and (1,7) has the next slope:
[tex]m=\frac{7-11}{1-3}=\frac{-4}{-2}=2[/tex]Slope-intercept form of a line:
y = mx + b
where m is the slope and b is the y-intercept
Replacing with m = 2 and point (3, 11):
11 = 2(3) + b
11 = 6 + b
11 - 6 = b
5 = b
Then, the equation is:
y = 2x + 5
