SOLUTION
Given the question in the image, the following are the solution steps to answer the question.
STEP 1: Create a relative frequency table
STEP 2: Calculate the relative frequencies for the two items
The relative frequency is gotten by dividing the columns by the total which is 50. this is done for both item A and item B and can be done as seen below:
[tex]\begin{gathered} item\text{ A} \\ relative\text{ frequency}=\frac{30}{50}=\frac{3}{5}=\frac{3}{5}\times100=60\% \\ \\ item\text{ B} \\ relative\text{ frequency}=\frac{20}{50}=\frac{2}{5}=\frac{2}{5}\times100=40\% \end{gathered}[/tex]
To get the relative frequency for item B, we do as seen below:
Using the table in Step 1,
Number of males who buys item B is 5
Number of female who buys item B is 15
Total customer for item B is 5+15=20
[tex]\begin{gathered} For\text{ male:} \\ \frac{5}{20}\times100=25\% \\ For\text{ female} \\ \frac{15}{20}\times100=75\% \end{gathered}[/tex]
Since the female has a higher relative frequency than the male, therefore it is reasonable to conclude that a customer who prefers item B is more likely to be a female than a male.
