Answer:
(4, -3)
Explanation:
Given the system of equations
[tex]\begin{gathered} x=2y+10 \\ 2x+3y=-1 \end{gathered}[/tex]
First, we rearrange as follows:
[tex]\begin{gathered} x-2y=10 \\ 2x+3y=-1 \end{gathered}[/tex]
Multiply the first equation by 2 to eliminate x.
[tex]\begin{gathered} 2x-4y=20 \\ 2x+3y=-1 \\ \text{Subtract} \\ -7y=21 \\ y=\frac{21}{-7} \\ y=-3 \end{gathered}[/tex]
Recall:
[tex]\begin{gathered} x-2y=10 \\ x-2(-3)=10 \\ x+6=10 \\ x=10-6 \\ x=4 \end{gathered}[/tex]
The solution as an ordered pair is: (x,y) = (4, -3)
