By logarithm quotient rule, it is define as:
[tex]\ln \mleft(\frac{x}{y}\mright)=\ln (x)-\ln (y)[/tex]
Based on the given problem:
[tex]\begin{gathered} \ln \mleft(\frac{3x-4}{x+2}\mright) \\ \text{The numerator is }3x-4 \\ \text{and the denominator is }x+2 \end{gathered}[/tex]
Therefore, we could rewrite it as
[tex]\ln \mleft(\frac{3x-4}{x+2}\mright)=\ln (3x-4)-\ln (x+2)[/tex]
