Respuesta :

Let the three angles be x,y,z.

By the Given conditon "The sum of the measures of the angles of a triangle is 180". It is clear that,

[tex]x+y+z=180^{\circ}[/tex]

By the given conditon " The sum of the measures of the second and third angles is three times the measure of the first angle". It is clear that,

[tex]y+z=3x[/tex]

Subsititute y+z=3x in the equation x+y+z=180,

[tex]\begin{gathered} x+y+z=180^{\circ} \\ x+3x=180^{\circ} \\ 4x=180^{\circ} \\ x=\frac{180}{4} \end{gathered}[/tex]

So by furthur simplifying the value of x can be founded,

[tex]\begin{gathered} x=\frac{180}{4} \\ x=45 \end{gathered}[/tex]

The value of x is 45 degree.

Subsitute the value of x in the equation y+z=3x. we get,

[tex]\begin{gathered} y+z=3x \\ y+z=3\times45 \\ y+z=135 \end{gathered}[/tex]

By the given condition "The third angle is 29 more than the second". It is clear that,

[tex]z=29+y[/tex]

Subsititute the equation z=29+y in the equation y+z=135,

[tex]\begin{gathered} y+z=135 \\ y+29+y=135 \\ 2y+29=135 \\ 2y=135-29 \\ 2y=106^{\circ} \\ y=53^{\circ} \end{gathered}[/tex]

The value of y is 53 degree.

Subsitute the value of x and y in the equation x+y+z=180. We get,

[tex]\begin{gathered} x+y+z=180^{\circ} \\ 45+53+z=180 \\ 98+z=180 \\ z=180-98 \\ z=82^{\circ} \end{gathered}[/tex]

The value of z is 82 degree.

So the value of x is 45 degree, the value of y is 53 degree and the value of z is 82 degree. That is,

[tex]x=45^{\circ},y=53^{\circ},z=82^{\circ}[/tex]