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A small object of mass 0.500 kg is attached by a 0.870 m - long cord to a pin set into the surface of a frictionless table top. The object moves in a circle on the horizontal surface with a speed of 7.85 m/s. What is the magnitude of the radial acceleration of the object?

Respuesta :

The radial acceleration formula is

[tex]a_c=\frac{v^2}{r}[/tex]

Where r = 0.870 m and v = 7.85 m/s. Let's replace these values and solve

[tex]\begin{gathered} a_c=\frac{(7.85m/s)^2}{0.870m}=\frac{61.62m^2/s^2}{0.870m}_{} \\ a_c\approx70.83m/s^2 \end{gathered}[/tex]

Hence, the radial acceleration is around 70.83 m/s2.