Respuesta :

In the figure above, ABCD is a trapezoid with EF as its midsegment;

Length of |AB| = 18

Length of |CD| = 26

The midsegment of the trapezoid is given as;

[tex]\begin{gathered} |EF|=\frac{1}{2}(|AB|+|CD|) \\ \end{gathered}[/tex][tex]undefined[/tex]

Ver imagen DivyaV591644