Respuesta :
ANSWER
[tex]\begin{equation*} 7.21\text{ m/s} \end{equation*}[/tex]EXPLANATION
Parameters given:
Initial height = 1.3 m
Initial speed = 8.8 m/s
Final height = 2.6 m
To find the speed of the tennis ball at a height of 2.6 m above the ground, we have to apply one of Newton's equations of motion:
[tex]v^2=u^2-2gs[/tex]where v = final speed
u = initial speed = 8.8 m/s
g = acceleration due to gravity = 9.8 m/s^2
s = distance traveled by the ball
Therefore, the speed of the ball at a height of 2.6 m (final speed) is:
[tex]\begin{gathered} v^2=8.8^2-(2*9.8*(2.6-1.3)) \\ \\ v^2=8.8^2-(2*9.8*1.3) \\ \\ v^2=77.44-25.48=51.96 \\ \\ v=\sqrt{51.96} \\ \\ v=7.21\text{ m/s} \end{gathered}[/tex]That is the answer.
