So,
Based in the information, we could draw:
Let "x" be the length of the longer leg.
We could find the dimentions of the triangle using the Pythagorean theorem:
[tex]\begin{gathered} (x+7)^2=x^2+(x-7)^2 \\ x^2+14x+49=x^2+x^2-14x+49 \\ x^2+14x+49=2x^2-14x+49 \\ \to x^2-28x=0 \end{gathered}[/tex]As you can see, we could solve this quadratic equation factoring:
[tex]\begin{gathered} x^2-28x=0 \\ x(x-28)=0 \\ x=0\text{ or }x=28 \end{gathered}[/tex]Note that the solution x=0 has not any sense in the context of the problem.
Therefore, the appropiate value of x is 28.
Now, we have found that the length of the longer leg is 28cm.
The shorter leg of the right triangle is 7 cm shorter than the longer leg, so its value is 21cm.
The hypotenuse is 7 cm longer than the longer leg, so, the value of the measure of the hypotenuse is 35cm.
