Answer:
Given that,
the variables q and d to represent the number of quarters in his collection and the number of dimes in his collection respectively.
The total value of his collection is $20.45. His collection consists of ten less quarters than three times the number of dimes.
we get,
q=3d-10
Also,
[tex]0.25q+0.1d=20.45[/tex]
Substitute q=3d-10 we get
[tex]0.25(3d-10)+0.1d=20.45[/tex][tex]0.75d-2.5+0.1d=20.45[/tex][tex]0.85d-2.5=20.45[/tex]
[tex]\begin{gathered} 0.85d=22.95 \\ d=\frac{22.95}{0.85} \end{gathered}[/tex][tex]d=27[/tex]
Substitute d in q=3d-10,
we get,
[tex]q=3(27)-10[/tex][tex]\begin{gathered} q=81-10=71 \\ q=71 \end{gathered}[/tex]
Enter the equations below separated by a comma.
q=3d-10 , 0.25q+0.10d=20.45
How many dimes are in his collection? The number of dimes is 27
How many quarters are in his collection? The number of quarters is 71
