Respuesta :
We are given that a mass of 9kg is hit by a force "F". According to Newton's second law we have:
[tex]F=ma_1[/tex]Plugging in the values we get:
[tex]F=(9kg)a_1[/tex]Now, we are given that a second block with a mass 45 kg is hit by the same force. Using newton's second law we get:
[tex]F=(45kg)a_2[/tex]Now, we divide both equations:
[tex]\frac{F}{F}=\frac{(9kg)a_1}{(45kg)a_2}[/tex]Now, we cancel out the "F":
[tex]1=\frac{(9kg)a_1}{(45kg)a_2}[/tex]Now, we multiply both sides by "a2":
[tex]a_2=\frac{(9kg)a_1}{(45kg)}[/tex]Simplifying we get:
[tex]a_2=\frac{1}{5}a_1[/tex]Therefore, the acceleration of the second block is one-fifth of the acceleration of the first block.
