Given:
Mass, m = 4 kg
ANgle of inclination,θ = 15°
Let's find the coefficient of static friction between the block and the surface.
To find the coefficient of static friction, apply the formula:
[tex]\begin{gathered} \mu_sN=fs \\ \text{Where:} \\ N=mg\cos \theta \\ \\ f_s=mg\sin \theta \end{gathered}[/tex]Thus, we have:
[tex]\begin{gathered} \mu_smg\cos \theta=mg\sin \theta \\ \\ \mu_s=\frac{mg\sin \theta}{mg\cos \theta} \\ \\ \mu_s=tan\theta \end{gathered}[/tex]Therefore, the coefficient of static friction will be:
[tex]\begin{gathered} \mu_s=\tan (15) \\ \\ \mu_s=0.267\approx0.27 \end{gathered}[/tex]Therefore, the coefficient of static friction between the blcok and the surface is 0.27
ANSWER:
