Given:
Given the magnitude of a vector is 2 and direction of a vector is 150 degrees.
Required: Component form of the vector
Explanation:
The components of the vector can be defined as
[tex]\begin{gathered} v_x=|v|\cos\theta \\ v_y=|v|\sin\theta \end{gathered}[/tex]
Substitute the given values.
[tex]\begin{gathered} v_x=2\cos150\degree \\ =-\frac{\sqrt{3}}{2} \\ v_y=2\sin150\degree \\ =1 \end{gathered}[/tex]
The given vector can be written in component form as
[tex]v=(-\frac{\sqrt{3}}{2},1)[/tex]
Final Answer: The component form of the given vector is
[tex]v=(-\frac{\sqrt{3}}{2},1)[/tex]
