From the statement of the problem, we know that:
0. y varies directly with x,
,
1. y = 6 when x = 3.
1) From point 1, we must have:
[tex]y=k\cdot x\text{.}[/tex]
2) From point 2 we know that y = 6 when x = 3, replacing these data in the last equation, we have:
[tex]6=k\cdot3.[/tex]
Solving for k, we get:
[tex]k=\frac{6}{3}=2.[/tex]
3) The equation is:
[tex]y=2x\text{.}[/tex]
Answer
• Equation: ,y = 2x
,
• Graph
