Given:
The sum of the three consecutive even intergers is 60.
Let 2a, 2a+2, and 2a+4 be the three consecutive even integers.
[tex]2a+2a+2+2a+4=60[/tex]
[tex]6a+6=60[/tex]
Subtracting 6 from both sides, we get
[tex]6a+6-6=60-6[/tex]
[tex]6a=54[/tex]
Dividing both sides by 6, we get
[tex]\frac{6a}{6}=\frac{54}{6}[/tex][tex]a=9[/tex]
The consecutive integers are
[tex]2\times9,2\times9+2\text{ and }2\times9+4[/tex]
[tex]18,20,22[/tex]
Hence the answer is
[tex]18,20,22[/tex]
