Given:
The length of a rectangle is 4 inches more than the width.
That is, l=w+4
The area is 45 square inches.
To find the dimensions:
The formula of area of the rectangle is,
[tex]\begin{gathered} A=l\times w \\ 45=(w+4)w \\ w^2+4w=45 \\ w^2+4w-45=0 \\ (w+9)(w-5)=0 \\ w=-9,4 \end{gathered}[/tex]Width can