Respuesta :
Let's draw a little diagram to help us answer this question:
• The first box can be the numerals ,0 to 9,, that is ,10 digits,.
,• The second box can be the numerals ,0 to 9,, that is ,10 digits,.
,• The third box can be the numerals ,0 to 9,, that is ,10 digits,.
,• The fourth box can be the numerals ,0 to 9,, that is ,10 digits,.
Then,
• Fifth box can have all the letters of the alphabet (26 of them) EXCEPT ,I, O, and X. ,That is 26 - 3 = ,23 letters,.
,• Sixth box can have all the letters of the alphabet (26 of them) EXCEPT ,I, O, and X. ,That is 26 - 3 = ,23 letters,.
,• Seventh box can have all the letters of the alphabet (26 of them) EXCEPT ,I, O, and X. ,That is 26 - 3 = ,23 letters,.
So, we can now see the rough diagram below with the number of elements in each of the 7 boxes:
From fundamental rule of counting, we need to multiply all of these to get the number of different licence plates possible. Shown below:
[tex]10\times10\times10\times10\times23\times23\times23=121,670,000[/tex]Answer121,670,000
