[tex]\begin{gathered} 2x-3y=60\ldots(1) \\ y=2x-5\ldots\text{.}(2) \\ \text{Substitute the value of y in the equation (1).} \\ 2x-3(2x-5)=60 \\ 2x-6x+15=60 \\ -4x=45 \\ x=-\frac{45}{4} \\ \text{Substitute the value of x in the equation (2).} \\ y=2\times-\frac{45}{4}-5 \\ y=-\frac{45}{2}-5 \\ y=-\frac{55}{2} \end{gathered}[/tex]
