[tex]\begin{gathered} (\frac{2}{5}-\frac{1}{10})\cdot2^3-\frac{23}{25} \\ \end{gathered}[/tex][tex]\begin{gathered} (\frac{3}{10})\cdot8-\frac{23}{25} \\ \frac{24}{10}-\frac{23}{25} \\ \frac{12}{5}-\frac{23}{25}=\frac{37}{25}=1\frac{12}{25} \end{gathered}[/tex]
Answer:
A.) 1 12/25
